6 (c) Fig 6-5 (a)The equation for the acceleration is given as A=(2 u)sin(管6)，S0 V-2 sin()d8=合w-cost停10] S=vd0=昌huw-sin(管) (b)The maximum peak)value of the acceleration is 5 units was given when日=是.s05 wnits-8Tg Ynaw=台u(0-是 2hu 今Vmax= 1.25units 8hw* TW Smax=hw (6=p) 582 →B mat=- hu =625Punits 8rhw Tw 53*Fig 6-5