Statics (4) Decomposition of a force along the coordinate axes If the three perpendicular components of a force along the coordinate axes are FF,and F then F=F+F+F Fr F due to F=Xi, F,=Yj, F=Zk O We get F=Xi+Yj+Zk ∴F=√X2+Y2+2 Z2 X Y COSC=-. COS F Cosy11 (4) Decomposition of a force along the coordinate axes: If the three perpendicular components of a force along the coordinate axes are then: Fx Fy Fz , and F =Fx +Fy +Fz 2 2 2 F= X +Y +Z F Z F Y F X cos= ,cos = ,cosg = F Xi F Yj F Zk due to x = , y = , z = We get F =Xi +Yj+Zk Fx Fy Fz