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2.Seismic Design 胞 Main Codes used for this prejet 2.Seismic Design 2.Seismic Design General design procedure General design procedure Step 1.Natural period e wmDT592.2) Fu=aG 6- a=0.16 2.Seismic Design General design procedure 3 3 The Third Floor  Main Codes used for this project Code for Seismic Design of Buildings GB50011-2001. (CSDB) Code for design of timber structures GB50005-2003. (CDTS) 2. Seismic Design  General design procedure Step 1. Natural period calculation (CDTS: 9.2.2) Empirical equation: T=0.05H0.75 Result: T=0.05H0.75=0.05×14.390.75=0.369s Step 2. Seismic influence coefficient definition (CSDB: 5.1.4, 5.1.5) 1 α = 0.16 —— Natural period calculation 2. Seismic Design Step 3. Horizontal seismic action calculation (CSDB: 5.2.1) FEK =α1Geq ( ) n EK n j jj ii i F HG G H F = −δ ∑ = 1 1 H3=5.395m H1=3.600m G3=665.984kN G2=1449.349kN G1=1440.476kN H2=3.600m F1=104.450kN F2=210.188kN F3=168.952kN 2. Seismic Design  General design procedure —— Seismic action calculation Step 4. Horizontal seismic action distribution between the wood-framed shear walls at each storey. • Action distribution according to the flexible diaphragms principle. (CSDB: 5.2.6) • It is assumed that walls with height-to-width ratio more than 3.5 do not resist the horizontal force. (CDTS: Appendix Q)  General design procedure —— seismic action distribution 2. Seismic Design First Plane
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