20kN/m 100kN 20kN B F -106.7 106.7 130 21.34+-42.68-64.0286.7433 -128.0 640-640 86.7-86.7 40 128 86.7 64 40 73.3 F1n×8 75.35 F=37.7 kN.m8m 4m 4m 4m 4m 2m A B E C F D G 20kN/m 100kN 20kN 杆件相对线刚度 i EI AB = 8 i EI BE = 4 i EI EC = 4 i EI CD = 8 杆端分配系数  BA = 2 5  BE = 3 5  CE = 2 3  CD = 1 3 固端弯矩 M M ql AB = − BA = − 2 12 = −  = − 20 8 12 106 7 2 . kN.m M Pl m CD = − + 3 16 2 = −   + = − 3 100 8 16 20 130 kN.m MDC = 20  2 = 40 kN.m 2 3 1 3 3 5 2 5 -106.7 106.7 -130 40 -21.34 -42.68 -64.02 -128.0 64.0 -64.0 86.7 43.3 86.7 -86.7 40 128 64 86.7 73.3 40 7535 8 4 1 . = F P  F1P = 37.7 kN.m