Continue Example 38.1 P1 Continue Solution: Theoretical Isentropic work output: P2 S2=S1=6.9212 kJ g.K S;(p2 =1bar)<s<sg(p2 =1bar) 2s >State 2s is in the two-phase region Graphical comparison of the S2-St(p2) three processes X,Fsp)-sp,） =0.928 h2=hr(p2)+x2he(p2)=2512.8 kJ kg →ws=h1-h2=(3230.9-2512.88 =718.02 kJ kg g .isentropic efficiency: -_wt=h,-h2=71.6% nr=- Wis h-h2 上降文通大学 May2,2018 12 SHANGHAI JIAO TONG UNIVERSITYMay 2, 2018 12 Continue Example 38.1 Continue Solution: • Theoretical Isentropic work output: • isentropic efficiency:                 s s s s s s s 2 1 f 2 g 2 2 2 f 2 2 g 2 f 2 2 2 f 2 fg 2 is 1 2 kJ s s 6.9212 kg K s p 1bar s s p 1bar s s p x 0.928 s p s p kJ h h p x h p 2512.88 kg kJ kJ w h h 3230.9 2512.88 718.02 kg kg                      State 2s is in the two-phase region T s p2 1 p1 2 S 2 Graphical comparison of the three processes s act 1 2 T is 1 2 w h h 71.6% w h h      