求塔顶采出率(D/F)及回收率(Dx/Fx); F=D+w 100=D+W FF=Dxn+m(2)100×0.4=09D+0.W 解方程组得 D=37.5 kmol/h W=625 kmol/h D/F=375/100 =0.375 DxD/FxF=0.375×0.9/(100×0.4) 0.8447 1. 求塔顶采出率( D / F ) 及回收率( DxD / FxF )； 解方程组得: D = 37.5 kmol/h W = 62.5 kmol/h D/F = 37.5/100 =0.375 DxD / FxF = 0.375×0.9 / ( 100×0.4 ) = 0.844   F = D +W (1)   100 = D +W ( 2) FxF = DxD +Wx W 100  0.4 = 0.9D + 0.1W