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P(Y=1)=PlUC=2mT+T =Ux=(n+02 =0 ∑ pg pg P(Y=-D)=Pl(X=2mz+ 3 p(UX=4m+32 0 ∑ 4m+3 pg pg = 0 1-qCh2-95 P(Y =1)       = = +  = ) 2 ( 2 0  m P X m         = = +  = ) 2 ( (4 1) 0  m P X m    = + = 0 4 1 m m pq 4 1 q pq − = P(Y = −1)       = = +  = ) 2 3 ( 2 0  m P X m         = = +  = ) 2 ( (4 3) 0  m P X m    = + = 0 4 3 m m pq 4 3 1 q pq − =
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