例2-1解答 △P H +Kq: H=12+Kg: pg 8+2g) 8 K=一 d dg 9.81×0.054×π2 0.024×05+7.6+1+05 =6.28×105s2/m3 H=12+6.28×105g 2 18.6 H=12+6.28×103× =28.76m 3600 P=P89H。=28.76×9.81×5.167×10-3×1000=1.458kW例2-1解答 2 H Kqv g    P 2 12 H Kq   v 2 4 4 2 5 2 5 8( ) 8 80 0.024 7.6 1 0.5 9.81 0.05 0.05 6.28 10 / l d K d g s m                        5 2 12 6.28 10 H q    v 2 5 18.6 12 6.28 10 28.76 3600 H m            3 28.76 9.81 5.167 10 1000 1.458 P gq H kW e v e         