2v:1→2 constant /and m 4F38c 2 3285C 0.7 MPa 1055M-CV 名-0.7MP 1,=21= 50.乃r ×311K=395.82K =m. 0.55 MPa Qy =mcy (T -T) =1.02kg×0.657J/(kg·K)×(395.85-311)K=56.84kJ p:2-3 constant p,but not m δQp=mc,dT -In R T 917J/kgK)×0.7×10°Pa×0.15m3 (285+273)K xIn =127.17k 260J/kg·K) 395.82K Q=9+Q,=56.84kJ+127.17kJ=184.01kJ 上游充通大 March 26,2019 7 SHANGHAI JLAO TONG UNIVERSITYMarch 26, 2019 7 QV：12 constant V and m 2 2 1 1 0.7 MPa 311 K 395.82 K 0.55 MPa p T T p         1 2 1 1.02 kg 0.657 J/(kg K) 395.85 311 K 56.84 kJ Q m c T T V V         Qp：23 constant p, but not m δ d Q mc T p p  3 2 d T p p T Q mc T   6 3 917 J/(kg K) 0.7 10 Pa 0.15 m (285 273) K ln 127.17 kJ 260 J/(kg K) 395.82 K          56.84 kJ 127.17 kJ 184.01 kJ Q Q Q      V p 3 2 3 3 3 2 d ln T p p T p V T c p V c T RT R T   