Example 1.11. Use Newton's square-root algorithm to find v5 Starting with po=2 and using formula(1.47), we compute 2+5/2 =2.25 225+5/2.25 =2.236111111 223611111+5/223611111 P3 2.236067978 2 236067978+5/2236067978 p4 =2.236067978