g (4)+=Log 3/=081 2.9 (1)Log(3)+=Logl 2=098 (2)P(黑/黑)= 14P自/黑=10 HY黑公m/-031 10 10 (3)P黑白)14P白白)=14 HY/白;Loe L 9/=09 (4)P黑严1P(白尸3 Lo =0918 2-10(1)H(色) 38)+18 38 (2)P(色数)=H(色数)=Log38)=5248 (3)H(数色)=H(色数}H(色)=5248-1245=4003 H(XYF 7)+1og(24)+0+-Log(24)+Log(4)+2A Log(24)+0+;1og(24 g(yD=7+1+0→1 2442|得到p0 244243 17 171 p(y3)=0+ (3)H(X/Y)=H(XY)-H(Y=2301-1.585=0716 2-12(1)恿X)=1球Y=1 H(XY=-Log8+-Lof 823+1083-181 H(YA=HXYH()=1811-1=0811 H(Y=HxY)HY)1811-1=0811 (3)1×Y=H0HwY=1-0811=0189 2-13(2) H= 1 4 Log(4) 3 4 Log 4 3       + = 0.811 2.9 (2) P(黑/黑)= P(白/黑)= H(Y/黑)= (3) P(黑/白)= P(白/白)= H(Y/白)= (4) P(黑)= P(白)= H(Y)= 2-10 (1) H(色)= (2) P(色数)= H(色数)= (3) H(数/色)= H(色数)- H(色)= 2-11 (1) H(XY)= 7 24 Log 24 7       1 24 + Log(24) + 0 1 24 + Log(24) 1 4 + Log(4) 1 24 + Log(24) + 0 1 24 + Log(24) 7 24 Log 24 7       + = 2.301 (2) P= 得到 H(Y)= (3) H(X/Y)=H(XY)-H(Y)= 2-12 (1) H(X) = 1 H(Y) = 1 (2) (3) 2-13