V2 Av1 a1Xiz1+a2X2x2+...+anXicn k=a11十a25a2十…+anXhin 均 a1+g+…+ = anTn) Whenk is sufficiently large,since=2,3,... vk≈1a1x1 is a eigenvector corresponding to A1. Copyright©2011，NA⊙Yin Last Modification:Oct.2011 10v2 = Av1 = α1λ 2 1x1 + α2λ 2 2x2 + · · · + αnλ 2 nxn ... vk = α1λ k 1x1 + α2λ k 2x2 + · · · + αnλ k nxn = λ k 1 (α1x1 + λ k 2 λ k 1 α2x2 + · · · + λ k n λ k 1 αnxn) When k is sufficiently large, since | λi λ1 | < 1, i = 2, 3, . . . , n vk ≈ λ k 1α1x1 is a eigenvector corresponding to λ1. Copyright c 2011, NAYin Last Modification: Oct. 2011 10