即FBy=16kN(个) 由∑F,=0得，FA,=8+4X4-16=8kN(个) (2)画剪力图和弯矩图 (6分) 8kN 8kN Fg图 8kN 16kN.m 8kN.m M图 28.(1)计算转动刚度和分配系数（令E1=1) (4分) 5队=4i队=4X号=1 ABA=0.4 Sc=4ic=4X是=1.5 8 4c=0.6 ScB=4icB=4X 81.5 cB=0.6 5w=3a=3×号-1 c=0.4 (2)计算固端弯矩 (4分) M8=-M8=-名P1=-g×I0×8=-1olkN·m M=-日·g·P=g×2×62=9kN·m 1644由~ Fy=O FAy = 8+4 X 4-16= 8kN (们 (2) 8kN (6 8kN 16kI' 8kN.m 28. (l)计算转动刚度和分配系数(令 1) SBA =4iBA=4X 专=1μBA = 0.4 1. SCB· 4i B=4X 1.5μCB =0.6 SCD=3icD=3×?=1μ♂0.4 (4 (2) 矩(4 MEc-MEBZ p. l = - m 12=÷ ←川 m 1644