力矩分配法的基本原理 用位移法计算图示刚架: LI MAB=4042n=HB·m A M=3i22∑m=c:m AD m=an·m ∑M2=0 MAC B A AB 4i1+32+3)4=m ADm m S S M i AD A AC AD A = = =   3   m m S S M i AC A AC AC A = = =   3 2   力矩分配法的基本原理 用位移法计算图示刚架： m m S S M i AB A AB AB A = = =   4 1    = 0 MA (4i 1 +3i 2 +i 3 ) A = m  = + +  = A A S m i i i m 1 2 3 4 3  m B A C D i 1 i 2 i 3 D C B A m MAB MAC MAD