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1 1/3 2 1/3 2/3 3 0 1 0 π0)=（经，2，） P 1/3 0 2/3 1/3 1/3 1/3 π四0=4(0,1,0)+(3,0，)+4(3,3，)1/3 1/3 1/3 1/3 2/3 1 1 2 3 P = ⇤ 010 1/302/3 1/3 1/3 1/3 ⇥ (0) = ( 1 ⌅ 4 , 1 2 , 1 4 ) (1) = 1 4 (0, 1, 0) + 1 2 ( 1 3 , 0, 2 3 ) + 1 4 ( 1 3 , 1 3 , 1 3 )