Axioms（公理)of probability For any propositions A,B ·0≤P(A≤1 P(true)=1 and P(false)=0 P(AVB)=P(A)+P(B)-P(AAB) True B 4口◆4⊙t1三1=，￥9QC . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Axioms（公理）of probability For any propositions A, B ▶ 0 ≤ P(A) ≤ 1 ▶ P(true) = 1 and P(false) = 0 ▶ P(A ∨ B) = P(A) + P(B) − P(A ∧ B)