综合选择指数的估计 6解:先求矩阵V、D、A、w,结果如下: p Cov(PD,, Ps, Cov (PD, PE,) Ov Cov(PS,, PE)A=Cov(4,, 42) 02 COv(A A2) 042 Cow(A1,A2)=r424·0 012.5×51=6375 Cov(PD, P=0 两性状间的遗传相关 Cov(PD,Ex A(PD PE) Cov(A,A)=0.5×6375=31.88 信息个体间的亲缘相关 Cov(Ps, PE)=Cov(A, Ae)= 212)=2)×042=0.×512=13005解：先求矩阵 ， 结果如下： 综合选择指数的估计           = 2 2 2 2 2 2 2 1 1 2 1 2 ( , ) ( , ) ( , ) P P S E P D S D E sym Cov P P Cov P P Cov P P    V ( , ) 0.1 12.5 51 63.75 1 2 1,2 1 2 Cov A A = rA  A  A =   = ( , ) 0 1 2 Cov PD PS = ( , ) ( , ) 0.5 51 1300.5 2 2 ( ) 2 2 2 2 2 2 2 S E = S E = A P P  A =  = s E Cov P P Cov A A r            = 2 1, 2 2 2 1, 2 2 1, 2 2 ( ) ( ) ( ) 1 A A A Cov A A Cov A A Cov A A    A V 、D、A、w ( , ) ( ) ( 1 , 2 ) 0.5 63.75 31.88 1 2 1 2 Cov P P = r Cov A A =  = D E A PD PE 两性状间的遗传相关 信息个体间的亲缘相关