例题分析 计算粗牙普通螺纫10和M68的螺旋升角,并说明 能否自锁y=0.1~0.15)。自锁条件:v≤p 解:1:M10,P=1.5m,d2=9.026m P 1.5 W1o =arcto=arcto 3.03 9.026丌 又:M68,P=6mm,d2=64.103mm P 6 Ae =ares d, -arcto 1.710 64.103元 2)∵B=0=30,∫=0.1 2 0.1 p =arct arcto =6.59 0 coS cos 30自锁条件：   例题分析 能否自锁（ ） 。 计算粗牙普通螺纹 和 的螺旋升角，并说明 0.1 ~ 0.15 10 68 f = M M 解： 1）M10，P = 1.5mm，d2 = 9.026mm 0 2 1 0 3.03 9.026 1.5  = = =    arctg d P arctg 又M68，P = 6mm，d2 = 64.103mm 0 2 6 8 1.71 64.103 6  = = =    arctg d P arctg30 , 0.1 2 2 0 = = f =  ） 0 0 6.59 cos 30 0.1 cos   = = arctg = f arctg  