习 题精解 解：AR和R。的表达式分析如下网 △4oL=B,{R2∥[e4+(1+B4)R]} △W1 2Tpel 模拟电子技术 B4{R∥[res+(1+Bs)R,] A2= Ao2=- △un Tpe4 +(1+B)Rs A6= △uo3二 (1+B3)R7 △uB Tpes +(1+Bs)R d.Aue a du:do △W灯 Ri =Tbel +rbe2 R。=R,∥'bes+R6 1+B5习 题 精 解 模 拟 电 子 技 术 解: 、Ri和Ro的表达式分析如下： Au     5 be5 6 o 7 i be1 be2 1 2 3 I O be5 5 7 5 7 I3 O 3 3 be4 4 5 4 6 be5 5 7 I2 O 2 2 be1 1 2 be4 4 5 I O1 1 1 (1 ) (1 ) (1 ) [ (1 ) ] 2 [ (1 ) ]         + + = = + =     = + + + =   = + + + + = −   = + + =   = r R R R R r r A A A u u A r R R u u A r R R r R u u A r R r R u u A u u u u u u u ∥ ∥ ∥