EXAMPLE Calculate the liquid junction potential for contact ofo.1MHCI andoImKcl at 250C. Common anion so negative and E1=-0.025916ln (349.82+7634)/(73.52+76.34)=-0.0259 *1n2.84=-27mVEXAMPLE Calculate the liquid junction potential for contact of 0.1 M HCl and 0.1 M KCl at 250C. Common anion so negative and EJ = - 0.025916 ln ((349.82+76.34)/(73.52+76.34)) = - 0.0259 * ln 2.84 = - 27 mV