n(N2) (978-2.20)kPa×416L 8.314J.K.mol×292K 0.164mol NHANO2(S)->2H20(8+ N2(g 6404g I mol 0.164mol 机邵学电國图 m(NHANO2)=? 6404g×0.164mol m(nano,) Imol =105gNH4NO2 (s) ⎯→ 2H2O(g) + N2 (g) 64.04g 1mol m(NH4NO2 )=? 0.164mol 8 314J K mol 292K (97 8 2 20)kPa 4.16L -1 -1    −  . . . n(N2 ) = 1mol 64.04g0.164mol m(NH4NO2 ) = =10.5g =0.164mol