已知：B=4×10-5T0=60°S=1m2 求：Φ 解：(1)Φ=B.S=BSc0s60° =4×105×1×0.5 =2×10-5Wb (2)Φ'=B.S=BSc0s30° =4×10-5×1×3 =3.46×105Wb Φ'=-3.46×105Wb 结束目录 B q 60 S 1m 0 2 = 4×10 = = 已知： -5 T 求：Φ 解：(1) . Φ = B S = BS cos 600 = 4×10-5×1×0.5 = 2×10-5 Wb = BS cos 300 3 = 4×10-5×1× 2 = 3.46×10-5 Wb Φ´´ = 3.46×10-5 Wb . (2) Φ´ = B S 结束 目录