Example 1.2. Consider the convergent iteration po=0.5 and ph+ for k=0.1 The first 10 terms are obtained by the calculations n1=e-0.5000000.606531 P2=e-0603=0.545239 P3=e-05239=0.579703 p=e-0.566409 0.567560 0.567560 p10=e =0.566907