The same analysis holds for the action of a →△L torque t As as shown in Fig 10-4. In this case Ai must be parallel to t We once again resolve T into two components∥L andt⊥ L. The component ∥/ ∥/ changes thei in magnitude ∥ but not in direction(Fig 10 L+△L 4a). The component△ gives an increment△L1⊥L which changes the direction of L but not its magnitude Fig 10-4 (Fig10-4b)(a) (b) → //  → ⊥  → L → L →  L// →  L⊥ → ⊥ → L+  L We once again resolve into two components and . The component changes the in magnitude but not in direction (Fig 10- 4a ). The component gives an increment , which changes the direction of but not its magnitude (Fig10-4b). → →  // // L → →  ⊥ ⊥ L → L → L →  ⊥  → →  L⊥ ⊥ L Fig 10-4 The same analysis holds for the action of a torque , as shown in Fig 10-4. In this case must be parallel to . t L   = → →  →  L →  →  → // 