解答 36解:单波,CM Pz2×(27×3×2 =51.57 Tbm=CMl=51.57×0025×154=19854(N·m) 单送,a=2,C Pz2×(27×3×2) 2xx2=25785 Tm=Cl。=9927(N·m) 100000 =516.53 0.88×220 Ⅰa=Ix 508.53A R Ea=UN-IaR-24l=220-50853×0022-2=2068V C Ea2068 0.376 550 Po=Pm-PN-EaNIo-PN=5164 60P0 60×5164 2m×X955C,p27×550×9503÷2497A 1o=l+l,=2497b 24.97+8=3297A R 解(1)T P=170065411N Q2、2n×3000 220 =1.2129 R181.5 1w=Ix-m=889-1212=87688A Ew=U-lR=220-87688×00896=21214V PmN= ENla=21214×87688=1860213w解答： 1－36 解：单波， 51.57 2 2 (27 3 2) 2 =    = = a  PZ C M = = 51.570.02515.4 =198.54 Tem CM I a  （N·m） 单迭，a＝2 ， 25.785 2 2 2 (27 3 2) 2 =     = = a  PZ C M = = 99.27 Tem CM I a  （N·m） 1－48 解： 516.53 0.88 220 100000 =  = = U P I N N N N  A = − = 508.53 R U I I f N aN N A = − R − 2u = 220 −508.530.022 − 2 = 206.8 EaN UN I aN a c V 0.376 550 206.8 = = = n E C N aN e N 5164 0 = − = − P = P PemN PN EaN I aN N w   C  P C T C T I M M M em a  = = = 0 0 0 0 ＝ 24.97 2 550 9.55 0.376 60 5164 2 9.55 60 0 =     =   C   P M n A 24.97 24.97 8 32.97 0 0 = + = + = + = R U I I I f N a f A 1－54 解（1） 54.1 2 3000 17000 60 =   = =   N N N P T N·m （2） = = = 1.212 181.5 220 R U I f N fN = − = 88.9 −1.212 = 87.688 I aN I N IfN A = − R = 220 −87.6880.0896 = 212.14 EaN UN I aN a V = = 212.1487.688 = 18602.13 PemN EaN I aN w