R1=△相邻电阻之积 R R R R3 △电阻之和 REb Any given arm of the Y network is found by taking the product of the two adjacent arms of the A network and dividing by the sum of the A network arms K'=k+k,+K' If ra=rb=r=r(balanced load) I then r=r=r2=R/3 +g+(5 y→△:(1)(2)+(2)(3)+(3)(1): Ka=k+k+\(3). R,R2+R2R3+r3R RRbR(R+R,+R) RRoR (Ra+r+r (Ra+Rb+r) (4)÷(3):Rn=(R1R2+R2R3+R3R1)/R3=R1+R2+R1R2/R3 (4)÷(1):R=(RR2+R2R3+R3R1)R1=R2+R3+R2R3/R1 (4)÷(2):R2=(R1R2+R2R3+R3R1)/R2=R3+R1+R3R1/R2Any given arm of the Y network is found by taking the product of the two adjacent arms of the Δ network and dividing by the sum of the Δ network arms. 电阻之和 相邻电阻之积   RY = If Ra=Rb=Rc=R (balanced load) then R1=R2=R3=R/3. Y   : (1) (2) (2) (3) (3) (1) : ' ' ' ' ' ' + + ' 1 2 2 3 3 1 2 (4) ( ) ( ) ( ) a b c a b c a b c a b c a b c R R R R R R R R R R R R R R R R R R R R R + + = + + + + + + = 1 2 2 3 3 1 3 1 2 1 2 3 ' ' (4)  (3) : Ra = (R R + R R + R R )/ R = R + R + R R / R 1 2 2 3 3 1 1 2 3 2 3 1 ' ' (4)  (1) : Rb = (R R + R R + R R )/ R = R + R + R R / R 1 2 2 3 3 1 2 3 1 3 1 2 ' ' (4)  (2) : Rc = (R R + R R + R R )/ R = R + R + R R / R ' 1 (1) a b c c a R R R R R R + + = ' 2 (2) a b c a b R R R R R R + + = ' 3 (3) a b c b c R R R R R R + + = a c b Ra Rb Rc a c b R1 R2 R3