冷由于 l(1) 050.593 l(2) (P)(R) 040.63-7 2(1) 0.80.244 (P2)⊙(R2) ⊙ 6345 2) 0.70.3 -19 因()=mx(0,20)}=max64=6 d1(1)=1 fi(2)=max q (2)a2)-mx3, 5} d1(2)=1❖ 由于 1(1) 1 1 1 1(2) 0.5 0.5 9 3 6 ( ) ( ) 0.4 0.6 3 7 3 q Q P R q         = =  =  =               − −   2(1) 2 2 2 2(2) 0.8 0.2 4 4 4 ( ) ( ) 0.7 0.3 1 19 5 q Q P R q         = =  =  =               − −   因而     1(1) 2(1) 1 f q q (1) max , max 6, 4 6 = = = 1 d (1) 1 =     1(2) 2(2) 1 f q q (2) max , max 3, 5 3 = = − − = − 1 d (2) 1 =