波导截止频率 k k2=丌 b2 实验中a=0.04b=002,取m=1,n=0 截止频率f=C/2a=3.75GHz (k。,(cB)+k,E) E0y=-12(k。、(B)-k。E0) cB kaE-k.a(cB COy=2(k0, Eo: +k, O, (cBo: )波导截止频率 • 实验中a=0.04 b=0.02 ,取m=1,n=0 • 截止频率f=c/2a=3.75GHz