例7计算pH=10.0时EBT的(pMg 已知:lgK(MgIn)=7.0 EBT:B1=101.662=10179 01n(HD1+10 10.0+16+10-20.0+179=1016 (pMgt-IgkMgIn)=gk(Mgn)-1gaIn(H) 7.0-1.6=545 例7 计算pH=10.0 时EBT的(pMg)t 已知： lgK(MgIn) = 7.0 EBT: 1 ＝1011.6 2 ＝1017.9 αIn(H) = 1 + 10-10.0+11.6 + 10-20.0+17.9 = 101.6 (pMg)t = lgK(MgIn) = lgK(MgIn) – lgαIn(H) = 7.0 – 1.6 = 5.4