8. 4. I solid surface and specific surface area (2) Degree of subdivision 400mJm×6×103m2=2400J arris Surface area Surface atom % cm 6 cm- 3×108 1um6×104cm2 30% lnm6×107cm ~100% (3)Specific area: The surface-to-volume/mass ratioarris Surface area Surface atom % 1 cm 6 cm2 3  10-8 1 m 6  104 cm2 30% 1 nm 6  107 cm2 ~ 100 % (2) Degree of subdivision (3) Specific area: V S Sv = W S Sw = The surface-to-volume / mass ratio 400 mJm-2  6  103 m2 = 2400 J 8.4.1 solid surface and specific surface area