=_Kodx y 2πx2+y7 yx X= m Ko y>0 y<0 Check boundary condition at y=0: Hx(y=0.)-Hx(y=0_)=-Ko -9-(2)=k 6.641,Electromagnetic Fields,Forces,and Motion Lecture 3 Prof.Markus Zahn Page 12 of 126.641, Electromagnetic Fields, Forces, and Motion Lecture 3 Prof. Markus Zahn Page 12 of 12 0 2 2 K dx y 2 x y = − π + 0 x 2 2 x K dx H y 2 x y +∞ = −∞ = − π + ∫ 0 1 x K y 1 x tan 2y y +∞ − =−∞ = − π 0 0 K y 0 2 K y 0 2 ⎧ − > ⎪ ⎪ = ⎨ ⎪+ < ⎪⎩ Check boundary condition at y=0: Hy 0 Hy 0 K xx 0 ( )( ) + − = − = =− 0 0 0 K K K 2 2 ⎛ ⎞ − − =− ⎜ ⎟ ⎝ ⎠