无机化学习题(01) 273 V =0.375× 294 设：金属的原子量为X MH2+2H20=M(0H)2+2H2↑ X+2 22.4×2 0.3263 0.375×273 =0.348 294 0.348X+0.696=22.4×2×0.3263 X=40 311DE08 解：生成氢气的物质的量为 101×0.129 n=(PV,RT ) =0.00522mo1 8.314×300 2A1+6HC1 2A1C13+3H2 54g 3mol X m= Zn 2HCl ZnCl2+H2 65 lmol 0.136-x n n=0.136-X) 65 有： (0.136-X) +3X =n+m=0.00522(mo1) 65 54 解，得：X=0.078 0.078 A10.136 ×100%=57.35% 8无机化学习题(01) 8 V =0.375× 273 294 设: 金属的原子量为 X MH2 + 2H2O = M(OH)2 +2H2↑ X+2 22.4×2 0.3263 0.375× 273 294 = 0.348 0.348X + 0.696 = 22.4 × 2 ×0.3263 X = 40 311DE08 解: 生成氢气的物质的量为 n=( PV, RT ) = 101×0.129 8.314×300 = 0.00522mol 2Al + 6HCl 2AlCl3+ 3H2 54g 3mol X m m = Zn + 2HCl ZnCl2+ H2 65 1mol 0.136-x n n = (0.136-X) 65 有: (0.136-X) 65 + 3X 54 = n + m = 0.00522(mol) 解,得: X=0.078 Al%=0.078 0.136 ×100%=57.35%