3)分解成冲激脉冲分量之和 f(t)=lil m∑f((t-1)=(t-1-4t)月△1/△ △t1→0 f(t0)=im∑f()6(t-1)△t1 △t1→0 0 f()=f(1)6(t-t 变量置换1→101→1 f()=∫f(8(-)d 此震邮电太辱电信工兽院北京邮电大学电信工程学院 6 (3) 分解成冲激脉冲分量之和 ∫ = − 0 0 0 0 ( ) ( ) ( ) t f t f t δ t t dt 变量置换 t → t t → t 0 1 ∫ = − t f t f t t t dt 0 1 1 1 ( ) ( )δ ( ) 1 1 0 1 0 0 ( ) lim ( ) ( ) 1 1 f t f t t t t t t t = ∑ − ∆ = ∆ → δ 1 1 1 1 1 0 1 0 ( ) lim ( )[ ( ) ( )] / 1 1 f t f t u t t u t t t t t t t t = ∑ − − − − ∆ ∆ ∆ = ∆ →