Numeric Range Relationship I TMin= TMax +1 Umax=2x TMax +1 1 has the same bit representation as Umax a string of all 1s Numeric value0 is represented as a string of all Os in both representations11 Numeric Range • Relationship – |TMin| = TMax + 1 – Umax = 2*TMax + 1 – -1 has the same bit representation as Umax, • a string of all 1s – Numeric value 0 is represented as • a string of all 0s in both representations