求取留数 B(s) 2+…+ -+kS) [r,p,k]=residue(num,den) A(s)s-ps-p, S-P B(s) 2s3+5s2+3s+6_-6,-43 A(s) +6s2+s+6s+3+2++2 rl= -6.0000 -4.0000 numl=2536: 3.0000 pl= denl=[16116 -3.0000 [rl,pl,kl]=residue(numl,den1) -2.0000 -1.0000 k= 2 School of Mechanical Engineering ME369-Lecture 4.5 Shanghai Jiao Tong University Fall 2015 求取留数（续） B=5+5++-+k6) [r,p,k]=residue(num,den A(s)s-P1S-P2 s-Pn B(s)s+1 -0.5-0.2887j,-0.5+0.2887j1 A(s)s3+s2+ss+0.5-0.866js+0.5+0.866js 2= -0.5000-0.2887i -0.5000+0.2887i 1.0000 p2= num2=11]: -0.5000+0.8660i den2=1110l: -0.5000.0.8660i [r2,p2,k2]=residue(num2,den2) 0 k2= 0 School of Mechanical Engineering ME369-Lecture 4.5 Shanghai Jiao Tong University Fa2015 33 ME369-Lecture 4.5 Fall 2015 School of Mechanical Engineering Shanghai Jiao Tong University 2 s 1 3 s 2 4 s 3 6 s 6s 11s 6 2s 5s 3s 6 A(s) B(s) 3 2 3 2                 num1=[2 5 3 6]; den1=[1 6 11 6]; [r1,p1,k1]=residue(num1,den1) r1 = -6.0000 -4.0000 3.0000 p1 = -3.0000 -2.0000 -1.0000 k1 = 2 k(s) s p r s p r s p r A(s) B(s) n n 2 2 1 1          [r,p,k]=residue(num,den) 求取留数 ME369-Lecture 4.5 Fall 2015 School of Mechanical Engineering Shanghai Jiao Tong University k(s) s p r s p r s p r A(s) B(s) n n 2 2 1 1          [r,p,k]=residue(num,den) s 1 s 0.5 0.866 j 0.5 0.2887 j s 0.5 0.866 j 0.5 0.2887 j s s s s 1 A(s) B(s) 3 2                num2=[ 1 1]; den2=[1 1 1 0]; [r2,p2,k2]=residue(num2,den2) r2 = -0.5000 - 0.2887i -0.5000 + 0.2887i 1.0000 p2 = -0.5000 + 0.8660i -0.5000 - 0.8660i 0 k2 = [] 求取留数（续）