其中: Y2=mX2=0.625×00498=00262 将各已知数值代入,得 50(0.0498-00024)=Vmin(0.0262-0 Tnm=90.46kmol(m2·h) =2 min 180.9kmol/(m2h) ∴L/V=50/180.9=0.276 0.0262 =0.0131 2 2 2021/2/21 上页下及2021/2/21 其中： 2 * Y2 = mX = 0.6250.0498 = 0.0262 将各已知数值代入，得： 50(0.0498 − 0.0024) =Vmin(0.0262 − 0) 90.46 /( ) 2 min V = kmol m  h 2 180.9 /( ) 2 min V = V = kmol m  h L/V = 50/180.9 = 0.276 2 * 2 2 Y Y = 2 0.0262 = = 0.0131