Engineering Simplification Axi-Symmetric Flow through Circular pipe 6 R r A=TI 6A=2πror Elemental discharge through elemental area δQ=v.SA=v.2πrδr Total Q through pipe section given by integration Q=vdA= 2nrvdr Mean velocity Vm=Q/a=Q/(TR2)Engineering Simplification Axi-Symmetric Flow through Circular Pipe Elemental discharge through elemental area : Q = v . A = v . 2rr Total Q through pipe section given by integration : Mean velocity Vm = Q/A = Q/(R2 ) r r R A = 2rr v A =r 2 Vm Q   = = A R Q vdA rvdr 0 2