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例:(2mo102298K,P)△G=→(373K,5P9) 7 :S09805Km0l,Cpmo)三方B 解:△G=△H(T2S2TS1) △H=nCm(T2T1)=4365J S=205×2=410J/K S2△S+S1 AS-nG Ln +nRLn P T 7 373 =2X RLn +2RLn- 2 298 e =-13.7J/K 5 例:(2molO2 298K,P θ )⎯G ⎯=? →(373K,5Pθ ) 已知:S  m(298K) =205J/Kmol, ( ) P m O2 C = 2 7 R 解:ΔG=ΔH-(T2 S2 -T1 S1) ΔH=nCP m(T2 -T1)=4365J S1 =205×2=410J/K S2 =ΔS+S1 ΔS=nCPmLn 1 2 T T +nRLn 2 1 P P =2× 2 7 RL n 298 373 +2RLn   P P 5 = -13.7J/K
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