Recitation 19 Now we set the right side equal to zero to find the best probability p p(n-1)(1-p) (1-p)=p(n-1) This answer makes sense, since we want the coin to come up heads exactly 1 time In n (d)What is the probability of success if p is chosen in this way? What quantity does this approach when n, the number of Immortal Warriors, grows large? Solution. Setting p=1/n in the formula for the probability that the experiment succeeds gives n In the limit, this tends to 1/e. McLeod is right� � Recitation 19 6 Now we set the right side equal to zero to find the best probability p: n(1 − p) n−1 = np(n − 1)(1 − p) n−2 (1 − p) = p(n − 1) p = 1/n This answer makes sense, since we want the coin to come up heads exactly 1 time in n. (d) What is the probability of success if p is chosen in this way? What quantity does this approach when n, the number of Immortal Warriors, grows large? Solution. Setting p = 1/n in the formula for the probability that the experiment succeeds gives: 1 n−1 Pr (E) = 1 − n In the limit, this tends to 1/e. McLeod is right