Example 44.1 Given: e P1=P4=140 kPa,ATsuperheat=5C,p2=p3=800 kPa,AT'supcooling= 5℃,Q=300k/min;nc=0.85 Find: ·X4=?(月,C0PR=?(),Wn=?(KW) Assumptions: 2 Steady state,steady flow ·Neglect△KE and△PE Adiabatic compression Constant pressure heat transfer processes No work or heat interactions in the expansion process 上游充通大学 May9,2019 21 SHANGHAI JIAO TONG UNIVERSITYMay 9, 2019 21 Example 44.1 Given: • p1 = p4 = 140 kPa, Tsuperheat = 5 oC, p2 = p3 = 800 kPa, Tsupcooling = 5 oC, QL = 300 kJ/min; ηc = 0.85 Find: • x4 =? (-), COPR = ? (-), Win =? (KW) Assumptions: T-s diagram: • Steady state, steady flow • Neglect KE and PE • Adiabatic compression • Constant pressure heat transfer processes • No work or heat interactions in the expansion process