eg. Calculate the thermodynamic efficiency, n, for an ideal heat engine operating between surface waters and water at 1000 m depth if the surface water temperature is 25C and the deeper is 5°C. Solution T=5C=278K T,=25C=298K 7=(1-T2/7n)=(1-278/298)=0.067=67% Of course the efficiency of an actual heat engine will be less than that 复旦大学环境科学与工程系 Department of Environmental Science and Engineering, Fudan Universityeg. Calculate the thermodynamic efficiency, η, for an ideal heat engine operating between surface waters and water at 1000 m depth if the surface water temperature is 25 o C and the deeper is 5 o C. (1 / ) (1 278 / 298) 0.067 6.7% 25 298 5 278 = − = − = = = = = = c h h c T T T C K T C K η   Solution: Of course, the efficiency of an actual heat engine will be less than that