(97.8-2.20)kPa×4.16L nN2尸 8.314J.K-.mol×292K =0.164mol NH4NO2(S)→2H2O(g)+ N2(g) 64.04g 1mol m(NHNO2=? 0.164mol m(NHANO2)= 64.04g×0.164mol 1mol =10.5gn(N2 )= =0.164mol NH4NO2 (s) ⎯→ 2H2O(g) + N2 (g) 64.04g 1mol m(NH4NO2 )=? 0.164mol m(NH4NO2 )= =10.5g 8 314J K mol 292K (97 8 2 20)kPa 4.16L -1 -1    −  . . . 1mol 64.04g0.164mol