Shandong University Physical Chemistry(2)Quarter Exam-2 2019-2020 Aoademmio Year Fall Semester 号国國五六[七九团十分分人 分■人 2020-2021 Academic Year. Fall Semester IL Fill the blanks with the best answers (4 points for each blank, totally The Second Quarter Exam of Physical Chemistry(2) [2-1] At 298.2 K, 0.005 mol kg CuSO4 solution obey Lewis empirical law, then the 舞分[人 L. Choose the best answer for the following questions using a cirele(4 points for 12-2] For cell Pu s)IHi(g, p)IH SO.(0. 1 mol kgr)Oa(g,pe))Pu(s), its electromotive force 密 each question, totally 20 points) is 1. V, when 2 mol electrons are transferred, A, He--28606 k mol, then energy 2 be constants, which conditions should be met electrochemical capacitance of Oz is 3350.7 mAh g. (Al, b, c, d; (B)a, b, e, d, e, (c)b, e, d; ( D)b, e, d, e. [2-3] The electrode reaction of Fe Fe O4- is 3Fe+80H--Fe:O4+4l a-strong electrolyte, b--infinite dilution, c-at constant temperature; d-in certain solvent; e-with certain counter ion. [I-2] Which of the following factor is not the reason for the high mean activity coefficient of [2-4]When we use Puc as catalyst for hydrogen evolution instead of Fe for electrolysis of 封 LiCI solution at high concentration. a NaCl solution and get 22.4 L (STP) hydrogen at a current density of I A dm-2, the electric energy saved is 94.57 k. (The a of Tafel equation for Pt and Fe is 0.07 and 0.56 while b is the same) 1.018-405X 10-(/C-25). When this cell discharge at 298.2 K, the reversible heat [2-5] The overpotential of hydrogen on Cu electrode is 0.23 V. If we want to perform (Ore)sent off by the cell is electrorefining of Cu using pure Cu as cathode and 0.2 mol kg-CuSO4 with 0.05 mol kg- (A)One>0, (B)One <0, (C)gre=0;(D)uncertain. [1-4) Usually, there is a discrepancy between the solubility product (K p) and ionic product Hasot as electrolyte without evolution of hydrogen. The potential of Cu cathode should (Kp)of an insoluble salt due to the formation of ionic pair. The discrepancy of which salts is keep higher than__-039_V. (without considering activity coefficient) (A)BaSO4(1.08×100;(B)CaSO4(1,96×104(C)PbSO4(1.06×103, (D)Agl(1.5×101) [1-5] The theoretical electromotive force of an H2-O2 fuel cell using a cationic polymeric (A)Ecat> Ean (B)Ec< Ean,(C)Eear- Ean: (D)uncertain. 第2019-2020 Academic Year Fall Semester 题号 一 二 三 四 五 六 七 八 九 十 总分 总分人 得分 2020-2021 Academic Year, Fall Semester The Second Quarter Exam of Physical Chemistry (2) ---------------------------------------------------------------------------------------------- 得分 阅卷人 I. Choose the best answer for the following questions using a circle (4 points for each question, totally 20 points) [1-1] For a given ion B, if we want its molar conductivity (B,m) and ionic mobility (UB) to be constants, which conditions should be met? (A)a, b, c, d; (B) a, b, c, d, e; (C) b, c, d; (D) b, e, d, e. a—strong electrolyte; b--infinite dilution; c—at constant temperature; d—in certain solvent; e—with certain counter ion. [1-2] Which of the following factor is not the reason for the high mean activity coefficient of LiCl solution at high concentration. (A) Severe hydration of Li+ ; (B) Strong repulsion between ions; (C) Decreased permittivity of water; (D) increased solution viscosity. [1-3] Fora reversible cell, its temperature dependence of electromotive forces is E/V = 1.018 – 4.05×10-5 (t/ oC-25). When this cell discharge at 298.2 K, the reversible heat (Qre) sent off by the cell is (A) Qre > 0; (B) Qre < 0; (C) Qre = 0; (D) uncertain. [1-4] Usually, there is a discrepancy between the solubility product (Ksp) and ionic product (Kip) of an insoluble salt due to the formation of ionic pair. The discrepancy of which salts is the largest? (A) BaSO4 (1.08×10-10); (B) CaSO4 (1.96×10-4 ); (C) PbSO4 (1.06×10-3 ); (D) AgI(1.5×10-16) [1-5] The theoretical electromotive force of an H2-O2 fuel cell using a cationic polymeric electrolyte (Ecat) or an anioic polymeric electrolyte (Ean) is (A) Ecat > Ean; (B) Ecat < Ean; (C) Ecat = Ean; (D) uncertain. 得分 阅卷人 II. Fill the blanks with the best answers (4 points for each blank, totally 24 points) [2-1] At 298.2 K, 0.005 mol kg-1 CuSO4 solution obey Lewis empirical law, then the activity of this solution is ___6.64×10-6____. [2-2] For cell Pt(s)H2(g, p)H2SO4(0.01 mol kg-1 )O2(g, p)Pt(s), its electromotive force is 1.229 V, when 2 mol electrons are transferred, rH m = -286.06 kJ mol-1 , then energy conversion efficient from chemical to electric is __82.92%___. The theoretical electrochemical capacitance of O2 is ___3350.7_mAh g-1 . [2-3] The electrode reaction of FeFe3O4OH￾is _3Fe + 8OH- ⎯→Fe3O4 + 4H2O + 8e-__. [2-4] When we use Pt/C as catalyst for hydrogen evolution instead of Fe for electrolysis of a NaCl solution and get 22.4 L (STP) hydrogen at a current density of 1 A dm-2 , the electric energy saved is __94.57_ kJ. (The a of Tafel equation for Pt and Fe is 0.07 and 0.56 while b is the same) . [2-5] The overpotential of hydrogen on Cu electrode is 0.23 V. If we want to perform electrorefining of Cu using pure Cu as cathode and 0.2 mol kg-1 CuSO4 with 0.05 mol kg-1 H2SO4 as electrolyte without evolution of hydrogen. The potential of Cu cathode should keep higher than ____-0.39_ V. (without considering activity coefficient) Shandong University Physical Chemistry (2) Quarter Exam-2 College Major Grade Student No. Name … … … … … … … … … … … … … … 密 … … … … … … … … … … 封 … … … … … … … … … … 线 … … … … … … … … … … … … … 第 1 页 共 2 页