Then RBLS? px=2op[责（∑2训-2NzA+N4 2wse(∑州-w} 1 h(x) g(∑x2(n),A) Sufficient statistics: whxiong@uestc.edu.cnwhxiong@uestc.edu.cn Then RBLS? = 1 (2¼A) N=2 exp ½ ¡ 1 2 µ 1 A Xx 2 [n] + NA ¶¾ | {z } g( Px2(n);A) ¢exp(Nx¹) | {z } h(x) Sufficient statistics: Xx 2 [n]