2015/10/25 Simplified Calculation of multiple Walls 60E IVH IV H u=3E Characteristic of multiple Walls Characteristic of multiple Walls stiffness of coupled beams mF刀m) D=Icla De D,阳 moment distribution coefficient mle walls israted total moment of rods:m=h beam's shear force: V=m(5)h/2c beam's end moment:M=d ↓Displacement axial force of walls:N,=∑Wy-yg-） oment ofa piece of wall.is distributed according =H 60 EI flexual moment IVH u二3Ela 本课件版权归作者所有，仅供个人学习使用，请勿转载。 52015/10/25 5 3 0 eq 3 0 eq 3 0 eq 11 V H u 60 EI 1 V H u 8 EI 1 V H u 3 EI    双肢墙 倒三角形分布荷载 均布荷载 顶部集中荷载 Displacement Coupled wall Inverted triangular distributed load Uniformly distributed load Concentrated load at the top of the strusture Simplified Calculation of multiple Walls Characteristic of multiple Walls 1. k+1 walls； 2. k coupled beams； stiffness of coupled beams： 3. integral coefficient expression of multiple walls is related with axial deformation coefficient; 4. coupled beams’ end moments are calculated on the basis of distribution coefficient / 0 2 3 D I c a i bi i i  0 bi bi bi 2 bi i I I 3 EI 1 GA a    moment distribution coefficient )] / i i i i i k i i i 1 i i i i m m D D 1 r r 1 4 B B               = （ ) : [1+1.5 (1- Characteristic of multiple Walls total moment of rods beam's shear force / beam's end moment axial force of walls: ( ) moment of a piece of wall, , is distr th i i th bi i th bi bi 0 n th i blj blj 1 l=i i m m h i V m h 2c i M V a i N V V j       ： = j （ ) ： =（ ) ： = = ibuted according to the flexual moment M ( ) n j ij k 1 Pi l l i l l i 0 j ij k 1 pi 0 j l i I M m I I V V I            3 0 eq 3 0 eq 3 0 eq 11 V H u 60 EI 1 V H u 8 EI 1 V H u 3 EI    Displacement 倒三角形分布荷载 均布荷载 顶部集中荷载 多肢墙 Coupled wall Inverted triangular distributed load Uniformly distributed load Concentrated load at the top of the strusture 本课件版权归作者所有，仅供个人学习使用，请勿转载