(S。/N 00M=3m2 (S/N0) 宽带调频的传输带宽BM与BM关系 Bm=2(4+fn)=2(m1m+m =2f0(m7+1)=B(m1+1) 当m时BmsB%BnM B (S0/N。) 0FM≈3( B FM2 (S0/N0)A B AM24 宽带调频的传输带宽BFM与BAM关系 2 0 0 0 0 3 ( / ) ( / ) f AM FM m S N S N = 2( ) 2( ) FM m f m m B = f + f = m f + f = 2 ( +1) = ( +1) m mf BAM mf f 当mf 1时 BFM  mf BAM AM FM f B B m  2 3( ) AM FM B B  AM FM S N S N ( / ) ( / ) 0 0 0 0