3.11-8 5 Known:Acme thread ~6 7 f=015,/,=0.15.d=i6m,2=29 Question:FindFfor applied force of6b,2.75 in.from the scre centerie. SoL P=L=1/6=0.1667” seca= 1=1.033 cosa d=d-05*p=1 =0.5417 812 { =F0,541701667+x*0.15*0.54171.033 =0.0696F 20.5417-0.15*0.1667*1.033 0.15*7 T=44=F6=0.0328F) 2 ∴.Ta=T+T-0.102F T=F●r=6b*2.75=16.51b-m 0.102F=16.5bim F-161.8b3. 11-8 f f F