2.管耗 P=m1+P2=2P=2P2 3.直流电源提供的功率 2VV C"0 2 M R TR 4效率 ACNO2(ccP 寸 Om 元 0n=41cc,==78.5%2.管耗 3.直流电源提供的功率 4.效率 PT = PT1 + PT 2 = 2PT1 = 2PT 2 L CC V M L CC m V R V P R V V P   2 0 2 , 2 = = CC m V V V P p 4 0  0  = = ) 4 2( 2 VCCV0m V0m = −  78.5% 4 4 , 0 = = =  V m VCC 