相图的用处4 S.J.T.U. Phase Transformation and Applications Page 7/34 Weight Percent Cadmium 0 300 ·求出活度数据 300 442℃ 20 一在两相共存区，某组 分在这两个共存相中 1480 的化学势应相等 (cd)- 36 40 60 0070 (sIn)= Alomie Percent Cadmium Lg (sIn)=uo +RT InaB LB)+RT In am AG=4W-4asT→Tm T △G=△Hm-T△Sm=△Hm(1- Solid->liquid T SJTU Thermodynamics of Materials Spring2008©X.J.Jin Lecture 18 Phase Diagram IVPhase Transformation and Applications S. J. T. U. SJTU Thermodynamics of Materials Spring 2008 © X. J. Jin Lecture 18 Phase Diagram IV Page 7/34 相图的用处 4 • 求出活度数据 – 在两相共存区，某组 分在这两个共存相中 的化学势应相等 D * )( ln)( Bi sBi s = μμ Bi Bi Bi lBi Bi sln)( ln aRT ln aRT * )( 0 μμ += μ += G lBi −=Δ sBi →TT m * )( * )( μμ )1( m m m m T T HSTHG −Δ=Δ−Δ=Δ Solid -> liquid