5.分别写出绕流固体圆球,圆球状液滴,圆球状汽泡时的边界条件 解:1)固体圆球:r=al=0,u1=0 r =Ucos, ue =-Usim 0,p=p 2)液滴 r=0l2ll为有限值 =0.u r-o u=Ucos,ue=-Usin0,p=p 3)气泡 r→>∞l1=Ucos6,lo=-Usn6,p=p 请注意上述情况均为轴对称运动。5. 分别写出绕流固体圆球,圆球状液滴,圆球状汽泡时的边界条件: 解: 1) 固体圆球: r = a u = 0,ur = 0 r → ur = U u = −U p = p cos, sin , 2) 液滴 r = 0 ur ,u 为有限值 r = a R R r u u u (1) (2) (1) (2) 0, = = = r → ur = U u = −U p = p cos, sin , 3)气泡 r = a 0 R = r → ur = U u = −U p = p cos, sin , 请注意上述情况均为轴对称运动